蔡欣辰SPYDER PYTHON二分法
pmt = [0,0,0,0] #劉任昌程式設計586設定串列list pmt[0]=float(input('躉繳金額: ')) for nper in range(1,4): pmt[nper] = float(input('第'+str(nper)+'期回收: ')) def npv(rate): y = - pmt[0] for j in range(1,4): y = y + pmt[j]/(1+rate)**j return y a, b, gap, f = 0.0, 1.0, 9.0, 9.0 maxerror = 0.000001 loopNumber = 1 while (gap > maxerror and abs(f) > maxerror and loopNumber maxerror and gap > maxerror): if ( f>0 ): a = c else: b = c gap = b-a; print('報酬率: ', c) print('淨現值: ', f) print('迴圈次數: ', loopNumber)
sin cos.https://takming123.blogspot.com/2025/05/buttonbordergreen-5px-solidborder_26.html
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